A) \[\frac{17}{35}\]
B) \[\frac{23}{31}\]
C) \[\frac{25}{35}\]
D) \[\frac{22}{35}\]
E) \[\frac{13}{35}\]
Correct Answer: D
Solution :
\[n(S){{=}^{7}}{{C}_{4}}=\frac{7\times 6\times 5}{3\times 2}=35\] \[\text{n(E)}{{\text{=}}^{\text{3}}}{{\text{C}}_{\text{2}}}{{\text{ }\!\!\times\!\!\text{ }}^{\text{4}}}{{\text{C}}_{\text{2}}}{{\text{+}}^{\text{3}}}{{\text{C}}_{\text{3}}}{{\text{ }\!\!\times\!\!\text{ }}^{\text{4}}}{{\text{C}}_{\text{1}}}\] \[\text{=81+4=22}\] \[\therefore \text{P(E)=}\frac{n(E)}{n(S)}=\frac{22}{35}\]
You need to login to perform this action.
You will be redirected in
3 sec
