(i) if\[x>y\] |
(ii) if\[x\le y\] |
(iii) if \[x<y\] |
(iv) if\[x\ge y\] |
(v) if\[x=y\]or relationship between\[x\]and\[y\]can't be established |
I. \[2x+5y=32\] |
II. \[5x-9y=-2\] |
A) if x>y
B) if x<y
C) if x<y
D) if x>y
E) if x=y or relationship between x and y can't be established.
Correct Answer: A
Solution :
I.\[2x+5y=32...\text{ }(i)\] II.\[5x-9y=-2~~~...(ii)\] Solving \[(i)\text{ }\times 9+(ii)\times 5,\]we get \[18x+25x=288-10\] or, \[43x=278\] \[\therefore x=\frac{278}{43}\] Putting the value of \[x\]in equation (i), we get \[2\times \frac{278}{43}+5y=32\] \[\Rightarrow 5y=32-\frac{556}{43}\] \[\Rightarrow y=\frac{1376-556}{43\times 5}=\frac{820}{215}\] Hence \[x>y\]You need to login to perform this action.
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