A) \[\frac{3}{7}\]
B) \[\frac{1}{7}\]
C) \[\frac{2}{5}\]
D) \[\frac{2}{7}\]
E) None of these
Correct Answer: B
Solution :
There are 7 letters, out of which 3 are vowels. \[\text{n}\left( \text{S} \right)\text{=7!}\] \[\text{n}\left( \text{E} \right)\text{ = 5!}\left( \text{3!} \right)\] \[\therefore \]Reqd probability \[=\frac{5!(3!)}{7!}=\frac{1\times 2\times 3}{6\times 7}=\frac{1}{7}\]You need to login to perform this action.
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