A) Rs.2300
B) Rs.2100
C) Rs.1900
D) Rs.2500
E) Rs.2900
Correct Answer: B
Solution :
\[\because \text{SI=}\frac{\text{T }\!\!\times\!\!\text{ P }\!\!\times\!\!\text{ r}}{\text{100}}\] or, \[2000=\frac{10000\times 2\times r}{100}\] \[\therefore r=10%\] Now, \[CI=P\left[ {{\left( 1+\frac{r}{100} \right)}^{n}}-1 \right]\] \[=10000\left[ {{\left( 1+\frac{10}{100} \right)}^{2}}-1 \right]\] \[=10000\times \frac{11\times 11}{100}-10000\] \[\text{=12100-10000=Rs}\text{.2100}\] Another Method: \[\text{Rate=}\frac{2000\times 100}{10000\times 2}=10%\] Now, rate of compound interest Then, \[10+10+\frac{10\times 10}{100}=21%\] Now, \[21%\] of 10000=Rs.2100You need to login to perform this action.
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