(i) if\[x>y\] |
(ii) if\[x\le y\] |
(iii) if \[x<y\] |
(iv) if\[x\ge y\] |
(v) if\[x=y\]or relationship between\[x\]and\[y\]can't be established |
I. \[{{x}^{2}}+16x+64=0\] |
II. \[{{y}^{2}}+11y=0\] |
A) if x>y
B) if x<y
C) if x<y
D) if x>y
E) if x=y or relationship between x and y can't be established.
Correct Answer: E
Solution :
Step II. \[+\frac{8}{1}\] \[+\frac{8}{1}\] Step III. \[x=-8\] II. \[{{y}^{2}}+11y=0\] Step I. \[y(y+11)=0\] Step II. \[y=0,-11\] Hence no relationship can be established between x and y.You need to login to perform this action.
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