A) 120m
B) 160m
C) 125m
D) 135m
E) None of these
Correct Answer: A
Solution :
Let the length of the train be x m. Then, \[\frac{x}{10}=\frac{x+120}{20}\] or, \[2x=x+120\] or, \[x=120\,\,m\] \[\therefore \]Length of the train \[=120\,\,m\] Logical Approach: \[T\to \]in 10 sec \[T+120\,\,m\to \]in 10 sec \[\Rightarrow \]\[120\,\,m\to \]in 10 sec \[\Rightarrow \]\[T=120\,\,m\]You need to login to perform this action.
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