A) 400
B) 375
C) 364
D) 539
E) 339
Correct Answer: E
Solution :
Let the three consecutive numbers be\[x,\,\,x+1\]and\[x+2\] Then,\[x+x+1+x+2=2031\] or,\[3x=2031-3\] or,\[3x=2028\] or, \[x=676\] The numbers are 676, 677 and 678. \[\therefore \]The highest number is 678. \[\therefore \]50% of 678 = 339 Quicker Method: Middle number is the average of 3 consecutive numbers. Middle no.\[=\frac{2021}{3}=677\] \[\Rightarrow \]Highest number\[=678\] \[\therefore \]50% of\[678=\frac{678}{2}=339\]You need to login to perform this action.
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