A) 28 years
B) 26 years
C) 22 years
D) 19 years
E) None of these
Correct Answer: B
Solution :
Let the age of Sunlit be 6x and that of Swati be 7x. Then, after 6 years \[\frac{6x+6}{7x+6}=\frac{15}{17}\] or, \[102x+102=105x+90\] or,\[3x=12\] or\[x=\frac{12}{3}=4\]years \[\therefore \]Age of Swati\[=4\times 7=28\]years \[\therefore \]2 years before age of Swati\[=28-2=26\]years Quicker Method: Present\[\to 6\] : \[7\times (17-15=2)=12\,\,\,\,:\,\,\,\,24\] \[\downarrow -3\]\[\downarrow +3\] +6 years\[\to 15\] : \[17\times (7-6=1)=15\,\,\,\,:\,\,\,\,17\] In ratio term, 3 = 6 years \[\therefore \]Age of Swati = 14 = 28 years \[\therefore \]Her age 2 years ago \[=(28-2=)26\] yearsYou need to login to perform this action.
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