Direction: Study the given chart carefully and answer the following questions. | |||||||||
Train A | |||||||||
Station | Arrival time | Departure time | Distance from origin (in km) | Number of passengers boarding at each station | Fare (in Rs.) | ||||
Ahmedabad | Starting | 5.00 pm | - | 400 | - | ||||
Vadodara | 630 pm | 635 pm | 100 | 100 | 50 | ||||
Bharuch | 8:50 pm | 9:00 pm | 250 | 90 | 120 | ||||
Mumbai | 400am | 4:10 am | 800 | 300 | 400 | ||||
Pune | 730 am | 7:45 am | 1050 | 150 | 500 | ||||
Solapur | 1020 am | Terminates | 1280 | - | 620 | ||||
Trial B | |||||||||
Station | Arrival time | Departure time | Distance from origin | Number of passengers boarding at each station | Fare (in Rs.) | ||||
Solapur | Starting | 6:00 pm | - | 300 | - | ||||
Pune | 7:40 pm | 7:45 pm | 230 | 150 | 120 | ||||
Mumbai | 9:30 pm | 9:35 pm | 480 | 270 | 220 | ||||
Bharuch | 5:40 am | 5:55 am | 1030 | 50 | 500 | ||||
Vadodara | 9:00 am | 9:10 am | 1180 | 100 | 570 | ||||
Ahmedabad | 12:00 noon | Terminates | 1280 | - | 620 |
A) 180%
B) 159.51%
C) 123.29%
D) 125%
E) 127.64%
Correct Answer: E
Solution :
Total income of Train \[A=(400\times 50)+(500\times 70)+(590\times 280)\]\[+(890\times 100)\]\[+(1040\times 120)=\]Rs.434000 Total income of Train \[B=(300\times 120)+(450\times 100)+\]\[(620\times 280)+(670\times 70)+(770\times 50)=\]Rs.340000 \[\therefore \]Reqd% \[=\frac{434000\times 100}{340000}\] = 127.64% of the total income of Train B.You need to login to perform this action.
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