| Direction: Study the table carefully to answer the following question. | ||||||||
| Station | Arrival time | Departure time | Distance travelled from origin (in km) | Fare (Rs.) | No. of passengers boarding the train at each station' | No. of pasengers dc boarding the train at each station | ||
| Adults | Children | Adults | Children | |||||
| Kanyakumari | Starting | 01:00 pm | - | 0 | 250 | 70 | - | - |
| Tirunelveli | 3 : 00 pm | 03 : 05 pin | 100km | Rs.80 | 320 | 90 | 100 | 20 |
| Tuticorin | 7 : 00 pm | 07 : !0 pm | 250km | Rs.200 | 150 | 70 | 50 | 30 |
| Madui'ai | 11:45 pm | 12:05 am | 430 km | Rs.310 | 100 | 60 | 230 | 50 |
| Tiruchirappalli | 3 : 35 am | 03 :40 am | 670km | Rs.450 | 120 | 40 | 80 | 30 |
| Arakkonam | 6 : 30 am | - 06 : 35 am | 820km | Rs.590 | 80 | 20 | 90 | 10 |
| Renigunta | 11 :00 am | terminates | 1140km | Rs.740 | - | - | - | - |
A) \[47\frac{5}{7}\,\text{kmph}\]
B) \[48\frac{4}{9}\,\text{kmph}\]
C) \[49\frac{1}{2}\,\text{kmph}\]
D) \[50\frac{3}{7}\,\text{kmph}\]
E) \[53\frac{11}{17}\,\text{kmph}\]
Correct Answer: E
Solution :
Total time taken by the train to travel from Kanyakumari to Renigunta \[=11\,am-\,pm=22\,\text{hours}\] Total halt time \[=5+10+20+5+5=45\]minutes If there in no halt then time taken \[=22hr-45\,\text{minutes}-21\,\text{hours}\,\text{15}\,\text{minutes}\] \[\therefore \]\[\text{Speed=}\,\frac{\text{1140}\,\text{km}}{\text{21}\,\text{hrs}\,\text{15}\,\text{minutes}}=\frac{1140\times 4}{85}\] \[=\frac{1140\times 4}{85}=\frac{912}{17}=53\frac{11}{17}\,\text{kmph}\]
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