| Direction: Study the table carefully to answer the following question. | ||||||||
| Station | Arrival time | Departure time | Distance travelled from origin (in km) | Fare (Rs.) | No. of passengers boarding the train at each station' | No. of pasengers dc boarding the train at each station | ||
| Adults | Children | Adults | Children | |||||
| Kanyakumari | Starting | 01:00 pm | - | 0 | 250 | 70 | - | - |
| Tirunelveli | 3 : 00 pm | 03 : 05 pin | 100km | Rs.80 | 320 | 90 | 100 | 20 |
| Tuticorin | 7 : 00 pm | 07 : !0 pm | 250km | Rs.200 | 150 | 70 | 50 | 30 |
| Madui'ai | 11:45 pm | 12:05 am | 430 km | Rs.310 | 100 | 60 | 230 | 50 |
| Tiruchirappalli | 3 : 35 am | 03 :40 am | 670km | Rs.450 | 120 | 40 | 80 | 30 |
| Arakkonam | 6 : 30 am | - 06 : 35 am | 820km | Rs.590 | 80 | 20 | 90 | 10 |
| Renigunta | 11 :00 am | terminates | 1140km | Rs.740 | - | - | - | - |
A) Rs.163400
B) Rs. 155980
C) Rs. 173500
D) Rs. 184000
E) Rs. 1925000
Correct Answer: B
Solution :
Total income of Railways from the train from Kanyakumari to Madurai = (fare of adult\[\times \] number of adults) + (fare of child\[\times \]number of children) \[=(250\times 80)+(70\times 80\times \frac{40}{100})+\{(250+320-100)\]\[(200-80)+(70+90-20)(200-80)\frac{40}{100}\}\]\[+\{(250+320-100+150-50)\times (310-200)+\]\[(70+90+70-20-30)\]\[(310-200\times \frac{40}{100})\}\] \[=\{(20000+2240)+(54600+6720)+(62700+7920)\}\] =Rs. 155980
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