Direction: Study the table carefully to answer the following question. | ||||||||
Station | Arrival time | Departure time | Distance travelled from origin (in km) | Fare (Rs.) | No. of passengers boarding the train at each station' | No. of pasengers dc boarding the train at each station | ||
Adults | Children | Adults | Children | |||||
Kanyakumari | Starting | 01:00 pm | - | 0 | 250 | 70 | - | - |
Tirunelveli | 3 : 00 pm | 03 : 05 pin | 100km | Rs.80 | 320 | 90 | 100 | 20 |
Tuticorin | 7 : 00 pm | 07 : !0 pm | 250km | Rs.200 | 150 | 70 | 50 | 30 |
Madui'ai | 11:45 pm | 12:05 am | 430 km | Rs.310 | 100 | 60 | 230 | 50 |
Tiruchirappalli | 3 : 35 am | 03 :40 am | 670km | Rs.450 | 120 | 40 | 80 | 30 |
Arakkonam | 6 : 30 am | - 06 : 35 am | 820km | Rs.590 | 80 | 20 | 90 | 10 |
Renigunta | 11 :00 am | terminates | 1140km | Rs.740 | - | - | - | - |
A) 40 kmph
B) \[60\frac{2}{19}\,\text{kmph}\]
C) \[62\frac{11}{21}\text{kmph}\]
D) 50 kmph
E) \[68\frac{15}{22}\text{kmph}\]
Correct Answer: A
Solution :
Speed of train between Kanyakumari and Madurai \[=\frac{430}{11.45\,\text{pm}-1.00\,\text{pm}}=\frac{430}{10.45}\] \[\frac{430}{10\frac{3}{4}}=\frac{430\times 4}{43}=40\,\text{kmph}\]You need to login to perform this action.
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