A) \[2L{{i}_{2}}O\xrightarrow[673K]{heat}L{{i}_{2}}{{O}_{2}}+2Li\]
B) \[2{{K}_{2}}O\xrightarrow[673K]{heat}{{K}_{2}}{{O}_{2}}+2K\]
C) \[2N{{a}_{2}}O\xrightarrow[673K]{heat}N{{a}_{2}}{{O}_{2}}+2Na\]
D) \[2Rb{{O}_{2}}\xrightarrow[673K]{heat}R{{b}_{2}}{{O}_{2}}+2Rb\]
Correct Answer: A
Solution :
[a] Lithium does not form peroxide.
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