A) both in cafionic and anionic parts
B) there is no zinc left in the solution
C) cationic part
D) anionic part.
Correct Answer: D
Solution :
[d] \[Z{{n}^{2+}}+2NaOH\xrightarrow{{}}\] \[Zn{{(OH)}_{2}}+2N{{a}^{+}}\] \[Zn{{(OH)}_{2}}+2NaOH\xrightarrow{{}}\] \[N{{a}_{2}}Zn{{O}_{2}}+2{{H}_{2}}O\] \[N{{a}_{2}}Zn{{O}_{2}}\xrightarrow{{}}2N{{a}^{+}}+{{(Zn{{O}_{2}})}^{2-}}\]You need to login to perform this action.
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