A) 1
B) \[-1\]
C) 0
D) None
Correct Answer: A
Solution :
[a] \[{{2}^{x+4}}{{.3}^{x+1}}=288\] \[{{2}^{4}}{{.2}^{x}}{{.3}^{x}}{{.3}^{1}}=288\] \[{{6}^{x}}=\frac{288}{48}=6\] x = 1You need to login to perform this action.
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