A) 14
B) \[-14\]
C) \[8\sqrt{3}\]
D) \[-8\sqrt{3}\]
Correct Answer: A
Solution :
[a] \[a=2+\sqrt{3}\] \[b=2-\sqrt{3}\] \[{{a}^{2}}=4+4+4\sqrt{3}\] \[{{b}^{2}}=4+3-4\sqrt{3}\] \[=7+4\sqrt{3}\] \[=7-4\sqrt{3}\] \[\frac{1}{{{a}^{2}}}+\frac{1}{{{b}^{2}}}=\frac{1}{7+4\sqrt{3}}+\frac{1}{7-4\sqrt{3}}\] \[=\frac{7-4\sqrt{3}+7+4\sqrt{3}}{49-48}\] = 14You need to login to perform this action.
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