A) + 16
B) \[-16\]
C) \[\pm \,16\]
D) None of these
Correct Answer: C
Solution :
\[{{(a+b+c)}^{2}}={{a}^{2}}+{{b}^{2}}+{{c}^{2}}+2\] \[(ab+bc+ca)\] \[\Rightarrow \] \[{{(a+b+c)}^{2}}\] \[=250+2\times 3=256\] \[\therefore \] \[a+b+c=\sqrt{256}=\pm \,16\]You need to login to perform this action.
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