The least number which when divided by 4, 6, 8 and 9 leave zero remainder in each case and when divided by 13 leaves a remainder of 7 is
A) 144
B) 72
C) 36
D) 85
Correct Answer:
B
Solution :
LCM of 6, 8, 9
2
4, 6, 8, 9
2
2, 3, 4, 9
3
1, 3, 2, 9
1, 1, 2, 3
\[\therefore \] LCM \[=2\times 2\times 3\times 2\times 3=72\] \[\therefore \] Required number = 72, Because it is exactly divisible by 4, 6, 8 and 9 and it leaves remainder 7 when divided by 13.