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SSC Sample Paper SSC CGL - Sample Paper-12

  • question_answer
    If a : b = c : d = e : f =   1 : 2, then (pa + qc + re) : (pb + qd + rf) is equal to

    A) \[p:(q+r)\]                     

    B) \[(p+q):r\]

    C) 2: 3                              

    D) 1: 2

    Correct Answer: D

    Solution :

    \[\frac{a}{c}=\frac{c}{d}=\frac{e}{f}=\frac{1}{2}\] \[\Rightarrow \]   \[\frac{pa}{pb}=\frac{qc}{qd}=\frac{re}{rf}=\frac{1}{2}\] \[\Rightarrow \]   \[\frac{pa+qc+re}{pb+qd+rf}=\frac{1}{2}\]


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