A) Rs. 1500
B) Rs. 1200
C) Rs. 1100
D) Rs. 1000
Correct Answer: D
Solution :
Let the sum be Rs. x. r = 10%, n = 3 yr \[SI=\frac{x\times r\times n}{100}\] \[SI=\frac{x\times 10\times 3}{100}=\frac{3}{10}x\] \[CI=\left[ {{\left( 1+\frac{r}{100} \right)}^{n}}-1 \right]x\] \[=\left[ {{\left( 1+\frac{10}{100} \right)}^{3}}-1 \right]x=\left[ {{\left( \frac{11}{10} \right)}^{3}}-1 \right]x\] \[=\left( \frac{1331}{1000}-1 \right)=\frac{331}{1000}x\] \[\frac{331}{1000}x-\frac{3}{10}x=31\] Or \[\frac{(331-300)}{1000}x=31\] Or \[\frac{31}{100}x=31\,\,or,\] \[x=1000\] \[\therefore \] Sum = Rs, 1000
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