A) \[55440\,c{{m}^{3}}\]
B) \[3465\,c{{m}^{3}}\]
C) \[7720\,c{{m}^{3}}\]
D) \[13860\,c{{m}^{3}}\]
Correct Answer: D
Solution :
Circumference of the base, \[C=2\pi r\] Where r = radius of the base or \[r=\frac{C}{2\pi }\] Given, \[C=66\,cm,\] \[h=40\,cm\] Volume \[=\pi {{r}^{2}}h\] \[=\pi {{\left( \frac{C}{2\pi } \right)}^{2}}h+\frac{{{C}^{2}}h}{4\pi }\] \[=\frac{66\times 66\times 40}{4\times \frac{22}{7}}c{{m}^{3}}\] \[=7\times 3\times 66\times 10\,c{{m}^{3}}\] \[=13860\,c{{m}^{3}}\]
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