A) Rs. 1352
B) Rs. 1377
C) Rs. 1275
D) Rs. 1283
Correct Answer: A
Solution :
A = Rs. 2550 R = Rs. 4% per annum, n = 2yr Let each of the two equal instalments be Rs. x. \[\text{Present worth}=\frac{\text{Instalment}}{{{\left( 1+\frac{r}{100} \right)}^{n}}}\] \[{{P}_{1}}=\frac{x}{{{\left( 1+\frac{4}{100} \right)}^{1}}}=\frac{x}{1+\frac{1}{25}}=\frac{x}{\frac{26}{25}}\] Or \[{{P}_{1}}=\frac{25}{26}x\] Similarly, \[{{P}_{2}}={{\left( \frac{25}{26} \right)}^{2}}x=\frac{625}{676}x\] \[{{P}_{1}}+{{P}_{2}}=A\] \[\therefore \] \[\frac{25}{26}x=\frac{625}{676}x=2550\] \[\Rightarrow \] \[\frac{(650+625)x}{676}=2550\] \[\Rightarrow \] \[\frac{1275}{676}x=2550\] \[\Rightarrow \] \[x=2550\times \frac{676}{1275}\] \[x=Rs.1352\]
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