A) 3 : 5
B) 5: 3
C) 17: 35
D) 35: 17
Correct Answer: C
Solution :
\[\frac{x}{y}=\frac{4}{5}\] \[\therefore \] \[\frac{3x+y}{5x+3y}=\frac{3\left( \frac{x}{y} \right)+1}{5\left( \frac{x}{y} \right)+3}\] \[=\frac{3\times \frac{4}{5}+1}{5\times \frac{4}{5}+3}=\frac{\frac{12+5}{5}}{7}=\frac{17}{35}\]
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