A) 20 min
B) 30 min
C) 40 min
D) 45 min
Correct Answer: A
Solution :
1 h = 60 min Rate of emptying the tank by the two taps are \[\frac{1}{60}\,\,\text{and}\,\,\frac{1}{30}\] of the tank per minute respectively. Rate of emptying the tank when both operate simultaneously. \[=\frac{1}{60}+\frac{1}{30}=\frac{1+2}{60}=\frac{3}{60}=\frac{1}{20}\] of the tank per \[\therefore \] Time taken by the two taps together to empty the tank = 20 minYou need to login to perform this action.
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