Kashish goes 30 m North, then turns right and walks 40 m, then again turns right and walks 20 m, then again turns right and walks 40 m. How many metres is he from his original position?
A)0
B)10
C)20
D)40
Correct Answer:
B
Solution :
The movements of Kashish are as shown in figure (A to B, B to C, C to D, D to E). \[\therefore \] Kashish's distance from his original position \[A=AE+(AB-BE)=(AB-CD)\] \[=(30-20)m-10\]