A) 6th, 13th, 20th, 27th
B) 7th, 14th, 21st, 28th
C) 4th, 11th, 18th, 25th
D) 3rd, 10th, 17th, 24th
Correct Answer: A
Solution :
We shall find the date on 1st June, 2005. 1st June, 2005 = (2004 yr + Period from 1.1.2005 to 1.6.2005) Odd days in 2000 yr = 0 4 yr = (1 leap year + 3 ordinary year) \[=(1\times 2+3)\,days\] = 5 odd days \[\begin{matrix} \text{Jan} & \text{Feb} & \text{March} & \text{April} & \text{May} & \text{June} \\ (31+ & 28+ & 31+ & 30+ & 31+ & 1) \\ \end{matrix}\] Total number of odd days (0 + 5 + 5) = 10 days = 3 days Therefore, 1st June, 2005 was Wednesday, So, 6th, 13th, 20th and 27th June 2005 are Monday.
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