A) Rs. 9900
B) Rs. 10092
C) Rs. 11000
D) Rs. 11052
Correct Answer: B
Solution :
Given, P = Rs. 7500, R = 16%, n = 2y \[\therefore \] \[A=P{{\left( 1+\frac{R}{100} \right)}^{n}}\] \[=7500{{\left( 1+\frac{16}{100} \right)}^{2}}\] \[=7500\times \frac{29}{25}\times \frac{29}{25}\] \[=12\times 841=10092\] \[\therefore \] \[A=Rs.\,10092\]You need to login to perform this action.
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