A) 24
B) 72
C) 36
D) 108
Correct Answer: B
Solution :
Let the third number = x \[\therefore \] The second number = 3x and first number \[=\frac{3x}{2}\] According to the question, \[x+3x+\frac{3x}{2}=3\times 44\] \[\Rightarrow \] \[\frac{2x+6x+3x}{2}=132\] \[\Rightarrow \] \[11x=264\] \[\Rightarrow \] \[x=\frac{264}{11}=24\] \[\therefore \] The largest number = 3x \[=2\times 24=72\]You need to login to perform this action.
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