A) \[\frac{17}{25}\]
B) \[\frac{18}{49}\]
C) \[\frac{23}{30}\]
D) \[\frac{23}{36}\]
Correct Answer: C
Solution :
Girls \[=\frac{3}{5},\] Boys \[=\left( 1-\frac{3}{5} \right)=\frac{2}{5}\] Fraction of students absent \[=\frac{2}{9}\,\,\text{of}\,\,\frac{3}{5}+\frac{1}{4}\,\,\text{of}\,\,\frac{2}{5}\] \[=\frac{6}{25}+\frac{1}{10}\] \[=\frac{21}{90}=\frac{7}{30}\] \[\therefore \] Fraction of students present \[=\left( 1-\frac{7}{3} \right)=\frac{23}{30}\]You need to login to perform this action.
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