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SSC Sample Paper SSC CGL - Sample Paper-15

  • question_answer
    Find the smallest multiple of 13 such that on being divided by 4, 6, 7 and 10, it gives remainder 2 in each case.

    A) 420                              

    B) 840

    C) 2470                            

    D) 2522

    Correct Answer: D

    Solution :

    \[4={{2}^{2}}\] \[6=2\times 3\] \[7=7\] \[10=2\times 5\] \[LCM=4\times 3\times 7\times 5=420\] Number \[=420k+2\]             \[=416k+(4k+2)\] When    \[k=6,\] then \[4k+2\] \[=4\times 6+2=26\] which is divisible by 13. \[\therefore \] Required number \[=420k+2\]             \[=420\times 6+2=2522\]


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