A) 2 cm
B) 3 cm
C) 6 cm
D) 9 cm
Correct Answer: C
Solution :
\[OD=OE=OF=2\,cm\] \[\therefore \] Area of \[\Delta \,ABC\] = Area of \[\Delta \,AOB\] + Area of \[\Delta \,BOC\] + Area of \[\Delta \,AOC\] \[\Rightarrow \] \[6=\frac{1}{2}\times AB\times 2+\frac{1}{2}\times BC\times 2+\frac{1}{2}\times CA\times 2\] \[\Rightarrow \] \[AB+BC+CA=6\,cm\]You need to login to perform this action.
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