A) 20 m, West
B) 10 m, East
C) 10 m, West
D) 10 m, North
Correct Answer: C
Solution :
The movements of Sachin are as shown in figure (P to B, B to C, C to D and D to Q). Clearly, distance of Q from P \[=PQ=(DQ-PD)=DQ-BC\] \[=(40-30)\text{ }m=10\text{ }m\] Also, Q is to the West of P. \[\therefore \] Q is 10m West of P.You need to login to perform this action.
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