A) 1m
B) 1 m 10 cm
C) 1 m 20 cm
D) 2 m
Correct Answer: B
Solution :
Sum of the heights of all the 24 students \[=(6\times 115+8\times 105+10\times 111)\,cm\] = 2640 cm \[\therefore \] Average height \[=\frac{2640}{24}=110\,cm\] = 1 m 10 cmYou need to login to perform this action.
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