A) \[24\,\text{c}{{\text{m}}^{\text{2}}}\]
B) \[32\,\text{c}{{\text{m}}^{\text{2}}}\]
C) \[48\,\text{c}{{\text{m}}^{\text{2}}}\]
D) None of these
Correct Answer: C
Solution :
Let base = x cm \[\therefore \] Side \[=\sqrt{64+\frac{{{x}^{2}}}{4}}\] \[\therefore \] \[x+2\sqrt{64+\frac{{{x}^{2}}}{4}}=32\] i.e., \[x+\sqrt{256+{{x}^{2}}}=32\] ...(i) Also, \[(256+{{x}^{2}})-{{x}^{2}}=256\] ...(ii) Dividing Eq. (ii) by Eq. (i), Subtracting Eq. (i) and Eq. (ii), \[2x=24\] \[\Rightarrow \] \[x=12\] \[\therefore \] Area of triangle \[=\frac{1}{2}\times 12\times 8=48\,\,sq\,\,cm\]You need to login to perform this action.
You will be redirected in
3 sec