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SSC Sample Paper SSC CGL - Sample Paper-18

  • question_answer
    Ravi and Ajay start simultaneously from a place A towards B, 60 km apart. Ravi's speed is 4 km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a place 12 km away from B. Ravi's speed is

    A) 12 km/h            

    B) 10 km/h

    C) 8 km/h 

    D) 6 km/h

    Correct Answer: C

    Solution :

    Let the speed of Ravi be x km/h. \[\therefore \] Ajay's speed \[=(x+4)\text{ km/h}\] Distance covered by Ajay \[=60+12=72\,\,km\] Distance covered by Ravi \[=60-12=48\,\,km\] According to the question,             \[\frac{72}{x+4}=\frac{48}{x}\] \[\Rightarrow \]   \[\frac{3}{x+4}=\frac{2}{x}\] \[\Rightarrow \]   \[3x=2x+8\] \[\Rightarrow \]   \[x=8\,\,\text{km/h}\]    


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