A) 4
B) 2
C) 2.199
D) 3.195
Correct Answer: B
Solution :
Let \[2.697=a\]and \[0.498=b\] \[\therefore \] Expression \[=\frac{{{(a-b)}^{2}}+{{(a+b)}^{2}}}{{{a}^{2}}+{{b}^{2}}}\] \[=\frac{2({{a}^{2}}+{{b}^{2}})}{{{a}^{2}}+{{b}^{2}}}=2\]You need to login to perform this action.
You will be redirected in
3 sec