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SSC Sample Paper SSC CGL - Sample Paper-19

  • question_answer
    If p = 999, then the value of \[\sqrt[3]{p({{p}^{2}}+3p+3)+1}\] is

    A) 1000    

    B) 999

    C) 998                              

    D) 1002

    Correct Answer: A

    Solution :

    \[\because \] \[p=999\] Now,     \[\sqrt[3]{p({{p}^{2}}+3p+3)+1}\]             \[=\sqrt[3]{{{p}^{3}}+3{{p}^{2}}+3p+1}\]             \[=\sqrt[3]{{{(p+1)}^{3}}}=p+1\]             \[=999+1=1000\]         


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