A) 1000
B) 999
C) 998
D) 1002
Correct Answer: A
Solution :
\[\because \] \[p=999\] Now, \[\sqrt[3]{p({{p}^{2}}+3p+3)+1}\] \[=\sqrt[3]{{{p}^{3}}+3{{p}^{2}}+3p+1}\] \[=\sqrt[3]{{{(p+1)}^{3}}}=p+1\] \[=999+1=1000\]You need to login to perform this action.
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