A) 10
B) 46
C) 70
D) 90
Correct Answer: A
Solution :
Suppose, 1st number is x, then 2nd number \[=100-x\] \[\therefore \] \[\text{LCM}\times \text{HCT =1st number}\times \text{2nd number}\] \[\Rightarrow \] \[495\times 5=x(100-x)\] \[\Rightarrow \] \[495\times 5=100x-{{x}^{2}}\] \[\Rightarrow \] \[{{x}^{2}}-55x-45x-2475=0\] \[\Rightarrow \] \[(x-45)(x-55)=0\] \[\Rightarrow \] \[x=45\] or \[x=55\] Then, difference \[=55-45=10\]You need to login to perform this action.
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