A) 58%
B) 67.5%
C) 78%
D) 82.5%
Correct Answer: C
Solution :
Let the number of boys and girls in the college be 3x and 2x respectively. Number of minor boys \[=3x\times \frac{80}{100}=\frac{12x}{5}\] Number of minor girls \[=2x\times \frac{75}{100}=\frac{3x}{2}\] Total number of minor students \[=\frac{12x}{5}+\frac{3x}{2}\] \[=\frac{24x+15x}{10}=\frac{39x}{10}\] Required percentage \[=\frac{39x}{10\times 5x}\times 100=78%\]You need to login to perform this action.
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