A) \[\div \] and \[\times ,\] 2 and 3
B) \[\times \] to \[-,\] 2 and 6
C) \[\div \] and \[\times ,\] 2 and 6
D) \[\times \] to \[-,\] 2 and 3
Correct Answer: A
Solution :
On changing \[\times \] to \[-\] and interchanging 2 and 3, we get the equation as \[(6\div 3)-2=0\] or \[2-2=0\]or \[0=0,\] which is true.You need to login to perform this action.
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