A) 60 m
B) 62 m
C) 62.5 m
D) 63 m
Correct Answer: C
Solution :
Let AB be a vertical stick and AC be its shadow. Also, let PQ be a tower having shadow PR. As \[\Delta ABC\sim \Delta PQR\] \[\therefore \] \[\frac{AB}{PQ}=\frac{AC}{PR}\] \[\Rightarrow \] \[\frac{15}{x}=\frac{12}{50}\] \[\Rightarrow \] \[x=\frac{15\times 50}{12}=62.5\,\,m\] Hence, height of the tower is 62.5 m.You need to login to perform this action.
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