A) 12 yr
B) 10 yr
C) 15 yr
D) 18 yr
Correct Answer: B
Solution :
Let Rs. P be the principal. \[\therefore \] \[3P=P{{\left( 1+\frac{r}{100} \right)}^{5}}\] \[3={{\left( 1+\frac{r}{100} \right)}^{5}}\] ? (i) Let the sum will be nine times in n yr. \[\therefore \] \[9P=P{{\left( 1+\frac{r}{100} \right)}^{n}}\] \[{{(3)}^{2}}={{\left( 1+\frac{r}{100} \right)}^{n}}\] ? (ii) \[n=10\,yr\]You need to login to perform this action.
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