A) 60
B) 40
C) 160
D) 280
Correct Answer: D
Solution :
Let the HCF of two numbers\[=x\] \[\therefore \] LCM of two numbers\[=14x\] Now, \[HCF+LCM=600\] \[x+14x=600\] or \[x=\frac{600}{15}=40\] \[\therefore \] HCF of two numbers \[=40\] And LCM of two numbers \[=14\times 40\] \[=560\] We know that \[\text{HCF}\,\,\text{ }\!\!\times\!\!\text{ }\,\,\text{LCM}\,\,\text{=}\,\,\text{Product of two numbers}\]\[40\times 560=80\times \text{Second number}\] \[\therefore \] \[\text{Second number}=\frac{40\times 560}{80}\] \[=280\]You need to login to perform this action.
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