A) AD: AC
B) AB: AD
C) AB: AC
D) AC: AB
Correct Answer: C
Solution :
As \[\angle B=2\angle C\] \[\Rightarrow \] \[\angle ABC=\angle BCA\] In \[\Delta ABC\] and \[\Delta ABD,\] \[\angle A=\angle A\] (Common) \[\angle ABD=\angle BCA\] (Proved) \[\therefore \] \[\Delta ABC\sim \Delta ABD\] \[\Rightarrow \] \[\frac{AB}{AD}=\frac{BC}{BD}=\frac{AC}{AB}\] \[\Rightarrow \] \[BD:BC=AB:AC\]You need to login to perform this action.
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