A) 6 : 1
B) 2 : 3
C) 3 : 2
D) 7 : 2
Correct Answer: A
Solution :
Let \[x=28=7\times 2\times 2\] and \[y=42=7\times 3\times 2\] \[\therefore \] HCF of x and \[~y=7\times 2=14\] and LCM of x and \[y=7\times 2\times 2\times 3=84\] \[\therefore \] Required ratio \[=84:14=6:1\]You need to login to perform this action.
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