A) 1
B) \[-\sqrt{3}\]
C) \[\sqrt{3}+\sqrt{2}\]
D) \[\sqrt{3}-\sqrt{2}\]
Correct Answer: B
Solution :
\[\frac{3\sqrt{2}}{\sqrt{6}-\sqrt{3}}-\frac{4\sqrt{3}}{\sqrt{6}-\sqrt{2}}-\frac{6}{2\sqrt{2}+2\sqrt{3}}\] \[=\frac{3\sqrt{2}(\sqrt{6}+\sqrt{3})}{\sqrt{6}-\sqrt{3}}-\frac{4\sqrt{3}(\sqrt{6}+\sqrt{2})}{\sqrt{6}-\sqrt{2}}\]\[-\frac{3(\sqrt{3}-\sqrt{2)}}{3-2}\] \[=\sqrt{2}(\sqrt{6}+\sqrt{3})-\sqrt{3}(\sqrt{6}+\sqrt{2})-3(\sqrt{3}-\sqrt{2)}\] \[=\sqrt{12}+\sqrt{6}-\sqrt{18}-\sqrt{6}-3\sqrt{3}+3\sqrt{2}\] \[=2\sqrt{3}-3\sqrt{2}-3\sqrt{3}+3\sqrt{2}\] \[=-\sqrt{3}\]You need to login to perform this action.
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