A) 1 : 1
B) 3 : 2
C) 2 : 3
D) 1 : 2
Correct Answer: C
Solution :
Let the first part is Rs. x and another part is \[Rs.(5000-x)\] According to question, \[\frac{x\times 6\times 1}{100}+\frac{(5000-x)\times 9\times 1}{100}=390\] \[\Rightarrow \] \[6x+45000-9x=39000\] \[\Rightarrow \] \[-\,3x=39000-45000\] \[\Rightarrow \] \[x=\frac{6000}{3}=2000\] \[\therefore \] First part \[=Rs.\,2000\] and second part \[=Rs.\,3000\] \[\therefore \] Required ratio \[=2:3\]You need to login to perform this action.
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