A) 1
B) 2
C) 3
D) \[\frac{1}{2}\]
Correct Answer: D
Solution :
\[\therefore \] \[\frac{{{M}_{1}}{{D}_{1}}}{{{W}_{1}}}=\frac{{{M}_{2}}{{D}_{2}}}{{{W}_{2}}}\] \[\therefore \] \[\frac{5\frac{1}{2}}{\frac{1}{48}}=\frac{6\times {{D}_{2}}}{\frac{1}{40}}\] \[\Rightarrow \] \[{{D}_{2}}=\frac{\frac{1}{2}\times 5\times 48}{40\times 6}=\frac{1}{2}\]You need to login to perform this action.
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