A) \[y=x+(4/x)\]
B) \[y=-2x+(4/x)\]
C) \[y=2x+(8/x)\]
D) \[y=2x-(8/x)\]
Correct Answer: D
Solution :
By given condition, \[y=lx+\frac{m}{x}\] ?(i) where l and m are proportionality constant. Where \[y=6,\] \[x=4,\] then \[6=4l+\frac{m}{4}\] \[\Rightarrow \] \[16l+m=24\] ?(ii) When \[y=\frac{10}{3},\] \[x=3,\] than \[\frac{10}{3}=3l+\frac{m}{n}\] \[\Rightarrow \] \[9l+m=10\] ?(iii) On solving Eqs. (ii) and (iii), we get \[l=2,\] \[M=-\,8\] From Eq. (i), \[y=2x-\frac{8}{x}\]You need to login to perform this action.
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